the inconsistency depending on fixpoint-selection

[bo198214]

then the resulting G0 and G1-matrices provide the same powerseries with a linear scaling.

I just see that this also works for exponentials \( b^x \), if there are two fixed points \( a_1 \) and \( a_2 \) then we have
\( b^{x+a_i}-a_i=b^{a_i} b^x- a_i = a_i b^x - a_i = a_i(b^x-1) \).
So the development at both fixed points are linear scalings of each other and both scalings of \( b^x-1 \).