Comparing the Known Tetration Solutions
#9
bo198214 Wrote:
Quote:Also, there's a question about whether you consider the slog function to only apply to the inverse of the function of iterated exponentials/logarithms from 1. For b=2, for example, the domain of slog is negative infinity to 2.
Dont understand this, \( t\mapsto \exp_2^{\circ t}(1.0) \) maps \( (-2,\infty) \) to \( (-\infty,\infty) \), so the slog is defined on \( (-\infty,\infty) \)?
Argh, sorry, I meant \( \sqrt{2} \). \( t\mapsto \exp_{\sqrt{2}}^{\circ t}(1.0) \) maps \( (-2,\infty) \) to \( (-\infty,2) \), so the slog is defined on \( (-\infty,2) \)
~ Jay Daniel Fox
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Messages In This Thread
RE: computing the iterated exp(x)-1 - by andydude - 08/17/2007, 11:20 PM
RE: computing the iterated exp(x)-1 - by jaydfox - 08/17/2007, 11:38 PM
RE: computing the iterated exp(x)-1 - by bo198214 - 08/17/2007, 11:45 PM
RE: computing the iterated exp(x)-1 - by jaydfox - 08/18/2007, 12:19 AM
RE: computing the iterated exp(x)-1 - by bo198214 - 08/18/2007, 08:19 AM
RE: computing the iterated exp(x)-1 - by andydude - 08/18/2007, 09:35 AM
RE: computing the iterated exp(x)-1 - by bo198214 - 08/18/2007, 11:59 AM
RE: computing the iterated exp(x)-1 - by jaydfox - 08/18/2007, 03:49 PM
RE: computing the iterated exp(x)-1 - by jaydfox - 08/19/2007, 12:50 AM

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