03/25/2008, 09:22 AM
Ivars Wrote:bo198214 Wrote:\( z={-1/\Omega} \)
The base in this case is positive, it is \( a=\Omega \), it is height \( z={-1/\Omega} \) that is negative.
Oh, right, I wasnt sure what you meant by \( z \), however now its clear that it is the right argument of tetration.
