complex iteration (complex "height")

[Ivars]

If we take the same but:

\( z={-1/\Omega} \)

And then I dont want to think about negative bases, perhaps first finish with bases \( e^{-1}<b<1 \)!

The base in this case is positive, it is \( a=\Omega \), it is height \( z={-1/\Omega} \) that is negative.

For all a<1 this formula will lead to negative heights:

\( a^{(1/a)} [4] {1/ln(a)} = 1 \)

Ivars