03/23/2008, 04:06 PM
bo198214 Wrote:Specialized to our case using the lower fixed point \( a \) we get the base by \( b=a^{1/a} \) and \( f'(a)=(b^x)'(a)=\ln(b)b^a=\ln(b)a=\ln(b^a)=\ln(a) \), so:
\( b[4]z=\exp_b^{\circ z}(1)=\lim_{n\to\infty} \log_b^{\circ n}(a(1-\ln(a)^z) + \ln(a)^z \exp_b^{\circ n}(1)) \)
Please just give still an explanation of what is this iteration -I am still not 100% sure I understand iteration symbols correctly.
\( \exp_b^{\circ n}(1)) \)
Thank you in advance,
Ivars

