Common difficulty. Sometime brain blocks...
Assume
Assume
(You had this right previous times
)
Gottfried
Assume
Code:
´
f(x) = x^2+2Code:
´
a) f(x)^2 = (x^2+2)^2 // taking f to the 2'nd power
= x^4 + 4x^2 +4
b) f°2(x) = f(f(x)) // iteration of f
= (f(x))^2 + 2
= (x^4 + 4x^2 +4) + 2
= x^4+4x^2+6
c) e^f(x) = ... // exponentiation of fAssume
Code:
´
f(x) = e^x
= 1 + x/1! + x^2/2! + ....Code:
´
a) f(x)^2 = (1 + x/1! + x^2/2! +...)^2 // taking f to the second power
= 1 + 2*x/1! + 4*x^2/2! + 8*x^3/3! + 16*x^4/4! +...
= f(2x)
b) f°2(x) = f(f(x)) // iteration of f
= f(e^x)
= 1 + e^x/1! + e^2x/2! + ...
c) e^f(x) = ... // exponentiation of f
// is in this case equal to second iteration(You had this right previous times
)Gottfried
Gottfried Helms, Kassel

