Interesting value for W, h involving phi,Omega?

[Ivars]

We can apply easily this to values of x^(1/x) if x is integer or unitary fraction.

If x=odd negative unit fraction, 1/n where n= odd, than:

(-1/n)^(-n) = 1/((-1/n)^n)= -n^n

If x=even negative unit fraction 1/m, where m=even:

(-1/m)^(-m)=1/((-1/m)^m)=m^m

so

h((-1/n)^(-n))= - 1/n if n odd, in this case argument in h is negative;
h((-1/m)^(-m))= -1/m if m even in this case argument in h is positive;

Examples:

h((-1/3)^(-3))=h(1/((-1/3)^3))= h(1/(-1/27)) =h(-27) = -1/3

h((-1/2)^(-2))=h(1/((-1/2)^2)))=h(1/(1/4))=h(4)= -1/2 ????

Inverting this:

h(-3^(-1/3))=h(1/((-3^(1/3)) ? there are 3 cubic roots of -3, 3^(1/3)*(cubic roots of -1).

3^(1/3)*(e^(ip/3), e^(-ip/3), -1)

All of them has the same value for h, namely h(-3^(-1/3))=h(1/((-3^(1/3)) =-3

h(-2^(-1/2))=h(1/((-2^(1/2))) / There are 2 square roots of -2 . 2^(1/2)*(-i; +i)

Both have the same value for h((-2^(-1/2))=-2.

I must be making some stupid mistake here.Please let me know so I do not continue

Ivars