Infinite tetration giving I*Omega costant=I*0.567143...
#11
bo198214 Wrote:
Ivars Wrote:\( lim (n->infinity) {\frac{\theta n}{n} = 1 \)

What do you mean by \( \theta n \)? Btw. \( \lim_{n\to\infty} \) has tex code
Code:
\lim_{n\to\infty}
.

Thanks. \( \theta n \) is n-th iteration of \( \theta \), starting with \( \theta=0 \), when n=0 .

It is the same as \( \theta \) in iteration formula (map) , while \( \theta' \) is next iteration result =angle \( \theta \) n+1, I just did not know how to add indexes in tex.

This limit is called rotation or winding number.

In my simulation, when n=1829, \( \theta n \)=1825.78027070570366694723301.... so

\( \theta n \)/1829=0.998239623130510479468142710945
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Messages In This Thread
RE: Infinite tetration giving I*Omega costant=I*0.567143... - by Ivars - 03/07/2008, 10:54 PM

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