Infinite tetration giving I*Omega costant=I*0.567143...
#9
I just came up with a numerical result I can not verify yet analytically, numerically my software is also poor, but:

Consider circle map (Arnold map) :


\( \theta'= \theta+\Omega-{\frac{K}{2*\pi}}*sin(2\pi\theta) \)

Let \( \Omega=0.567143.. \)

And \( K= {\frac{\pi}{2*\Omega}.. \)

then map becomes:

\( \theta'= \theta+\Omega-{\frac{1}{4*\Omega}}*sin(2\pi\theta) \)

I did 1800 iterations with 50 digit accuracy ( This was my first try) and the resulting conjecture is:

\( lim (n->infinity) {\frac{\theta n}{n} = 1 \)

monotonically from below, no oscillations. So the resulting angle is 1 rad again. I was expecting it,as \( \Omega \) seems to be kind of a self frequency of a flow on unit circle? But than I do not know much about circle maps. Perhaps that is true for any \( \Omega \)? Not only Omega constant?

Ivars
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RE: Infinite tetration giving I*Omega costant=I*0.567143... - by Ivars - 03/07/2008, 09:19 PM

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