Interestingly, if we take
z=I*ln(phi)= I* ln(1.6180399..) and
z =I*logomega (phi)= I* (ln(1.6180399..)/ln(Omega))= -0.8484829....,
using:
sin (z) = (-I/2)* (Omega^(z/(I*Omega))-Omega^(-z/(I*Omega))),
cos (z) = (1/2)*((Omega^(z/(I*Omega))+Omega^(-z/(I*Omega)))
sin(I*logomega (phi))= (-I/2)
cos (I*logomega (phi)) = (1/2) *(sqrt(5))= phi-1/2=1.6180399-0.5=1.1180399
but (I/2)=sin(I*ln(phi), so
sin(I*ln(phi)*sin(I*logomega (phi)) = 1/4
sin(I*ln(phi)+sin(I*logomega (phi)) =0
sin(I*ln(phi)/sin(I*logomega (phi)) =-1
sin(I*ln(phi)-sin(I*logomega (phi)) =-I
Ivars
z=I*ln(phi)= I* ln(1.6180399..) and
z =I*logomega (phi)= I* (ln(1.6180399..)/ln(Omega))= -0.8484829....,
using:
sin (z) = (-I/2)* (Omega^(z/(I*Omega))-Omega^(-z/(I*Omega))),
cos (z) = (1/2)*((Omega^(z/(I*Omega))+Omega^(-z/(I*Omega)))
sin(I*logomega (phi))= (-I/2)
cos (I*logomega (phi)) = (1/2) *(sqrt(5))= phi-1/2=1.6180399-0.5=1.1180399
but (I/2)=sin(I*ln(phi), so
sin(I*ln(phi)*sin(I*logomega (phi)) = 1/4
sin(I*ln(phi)+sin(I*logomega (phi)) =0
sin(I*ln(phi)/sin(I*logomega (phi)) =-1
sin(I*ln(phi)-sin(I*logomega (phi)) =-I
Ivars

