Interesting value for W, h involving phi,Omega?

[Ivars]

I Need to add few more formulae and check before we can explain(? ) oscillations related to Omega and W(1):

Omega^(1/(I*Omega) = e^I

Omega^(-1/(I*Omega)=e^-I

sin (z) = (-I/2)* (Omega^(z/(I*Omega))-Omega^(-z/(I*Omega)))
cos (z) = (1/2)*((Omega^(z/(I*Omega))+Omega^(-z/(I*Omega)))

So if so if z has simple form (p/q)*I*Omega,

sin((p/q)*I*Omega)=(-I/2)* (Omega^(p/q)-Omega^-(p/q))

if p=q=1,

sin((I*Omega)=(-I/2)*(Omega-1/Omega) = (-I/2)*1,19607954..=-I*0,59803977..
Cos(I*Omega)=(1/2)*(Omega+1/Omega) =(1/2)*2.330366124=1,161830623...

This corresponds to angle -0,64105..rad= -36,7297..grad

Also

(I*Omega)^(1/Omega) =-0.342726848178+I*0.13369214926..

Module ((I*Omega)^(1/Omega)) = 1/e = Omega^(-1/Omega)

Arg ((I*Omega)^(1/Omega)) = atan(-2,5632)=-1,198826..rad = -68,6876759..grad

An Interesting complex number with module 1/e.

The angle between these 2 formula values is 2,1988261.. rad =125,983.. degrees.

(1/(I*Omega))^Omega = 0.86728..- I* 1.07264..

Module ((1/(I*Omega))^Omega ) = Omega^Omega

Arg ((1/(I*Omega))^Omega ) = atan(-0.808545..)= -0.67993..rad = -38. 957 degrees

Ivars