01/31/2008, 11:50 PM
bo198214 Wrote:However it seemed as if couldnt see the wood because all those trees:
Of course \( h(x) \) is the inverse function of \( x^{1/x} \).
And thatswhy it is clear that \( h(x^{1/x})=x \),
especially for \( x=I/n \).
Also for x= I/y, y -real>1?
Ivars

