Has anyone studied the iterates of \( \frac{1}{e^{-1/z}} \)?
\[\frac{1}{e^{-1/z}}=e^{1/z}\]
\[\frac{1}{e^{-\frac{1}{e^{-1/z}}}}=e^{e^{1/z}}\]
\[\frac{1}{e^{-\frac{1}{e^{-\frac{1}{e^{-1/z}}}}}}=e^{e^{e^{1/z}}}\]
\[\frac{1}{e^{-1/z}}=e^{1/z}\]
\[\frac{1}{e^{-\frac{1}{e^{-1/z}}}}=e^{e^{1/z}}\]
\[\frac{1}{e^{-\frac{1}{e^{-\frac{1}{e^{-1/z}}}}}}=e^{e^{e^{1/z}}}\]
Daniel

