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using (5/2)x - (5/6)x^3 + ...

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using (5/2)x - (5/6)x^3 + ...
tommy1729 Offline
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#4
04/29/2023, 11:00 PM
I will analyse f(x) = exp(x) - exp( - e x) in the next thread.


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tommy1729
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Messages In This Thread
using (5/2)x - (5/6)x^3 + ... - by tommy1729 - 04/25/2023, 11:25 PM
RE: using (5/2)x - (5/6)x^3 + ... - by tommy1729 - 04/26/2023, 12:27 PM
RE: using (5/2)x - (5/6)x^3 + ... - by tommy1729 - 04/26/2023, 11:29 PM
RE: using (5/2)x - (5/6)x^3 + ... - by tommy1729 - 04/29/2023, 11:00 PM



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