[MSE] f(f(z)) = z , f(exp(z)) = exp(f(z))

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[MSE] f(f(z)) = z , f(exp(z)) = exp(f(z))

tommy1729 Offline

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03/17/2023, 12:53 AM

Mick edited his question with a carleman matrix idea.

both on MSE and MO.

regards

tommy1729

ps : this actually shows ( i think ) that the carleman matrix method does not agree with the infinite composition methods ( early 2020 ?) having 2pi i periodicity.

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Messages In This Thread

[MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by tommy1729 - 03/11/2023, 11:27 PM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by tommy1729 - 03/14/2023, 11:23 PM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by Daniel - 03/15/2023, 12:53 AM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by JmsNxn - 03/16/2023, 03:56 AM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by tommy1729 - 03/17/2023, 12:48 AM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by tommy1729 - 03/17/2023, 12:53 AM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by JmsNxn - 03/18/2023, 03:37 AM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by Daniel - 03/18/2023, 05:16 AM

RE: [MSE] f(f(z)) = z , f(exp(z)) = exp(f(z)) - by JmsNxn - 03/18/2023, 05:54 AM