exp(x) x f ' (exp(x)) = exp(f(x)) f(x)
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exp(x) x f ' (exp(x)) = exp(f(x)) f(x)
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02/18/2023, 12:26 AM
(02/18/2023, 12:14 AM)tommy1729 Wrote: A simple idea comes to mind for x > 1 : maybe ... confusing lol |
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exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/12/2023, 11:28 PM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/12/2023, 11:41 PM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by JmsNxn - 02/14/2023, 05:41 AM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/14/2023, 09:30 PM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by JmsNxn - 02/16/2023, 05:02 AM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/17/2023, 11:53 PM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/18/2023, 12:04 AM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/18/2023, 12:14 AM
RE: exp(x) x f ' (exp(x)) = exp(f(x)) f(x) - by tommy1729 - 02/18/2023, 12:26 AM
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