exp(x) x f ' (exp(x)) = exp(f(x)) f(x)

[tommy1729]

Yes yes I know this is all far from formal.

And all iterations of exp or ln commute compositionally with exp(x) and ln(x).
So that might create issues.

Im just explaining the main idea.

It is thus not formally confirmed that one of the solutions is smaller than semi-exp.

And the amount of solutions and their structure is also unclear.

Then again those are good reasons to investigate not ?


regards

tommy1729