02/10/2023, 04:00 AM
(02/10/2023, 03:55 AM)Caleb Wrote: If I understand correctly, questions about whether the function has a natural boundary should reduce into how 'predictable' \( A(x) \) is.
Yes, and vice versa
So far though, I've only been able to really grok that the zeta function (it's summation/integral form at least) only converges for \(\Re(s) > 0\). I'm taking your word it goes even to \(\Re(s) > -1\)--but it doesn't suprise me

