01/20/2023, 08:41 PM
btw i believe in your conjecture
regards
tommy1729
regards
tommy1729
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Maybe the solution at z=0 to f(f(z))=-z+z^2
Maybe the solution at z=0 to f(f(z))=-z+z^2
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Maybe the solution at z=0 to f(f(z))=-z+z^2
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Maybe the solution at z=0 to f(f(z))=-z+z^2 - by Leo.W - 01/19/2023, 06:31 PM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by tommy1729 - 01/19/2023, 11:20 PM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by Leo.W - 01/20/2023, 05:19 AM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by Leo.W - 01/20/2023, 01:35 PM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by tommy1729 - 01/20/2023, 08:33 PM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by Leo.W - 01/22/2023, 07:12 AM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by Leo.W - 01/22/2023, 07:51 AM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by tommy1729 - 01/20/2023, 08:41 PM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by JmsNxn - 01/23/2023, 01:34 AM
RE: Maybe the solution at z=0 to f(f(z))=-z+z^2 - by tommy1729 - 01/24/2023, 12:37 AM
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