01/23/2008, 10:20 AM
I'd like to finish it even if it is wrong:
So we take :
dI/dp= p*(h((I/p)^(p-2I)/I* ln(I/e*p) - I/(p^2))
And put it =0 to find minimum:
We have 2 solutions : p=0 and
h((I/p)^(p-2I)/I* ln(I/e*p) - I/(p^2)=0
h(((I/p)^(p-2I)/I)*ln(I/e*p))= I/(p^2) we can make substitution p^2=q
Than from earlier, if h( function) = I/q then from another thread http://math.eretrandre.org/tetrationforu...hp?tid=110
function = (I/q)^(q/I)
so (((I/(q^(1/2))^(q^(1/2)-2I)/I))*ln(I/(e*(q^(1/2)))) = (I/q)^(q/I)
So we can find q and p, probably both complex numbers.
The idea was, this should give the minimum of Gottfrieds curve in the left upper corner , where Re ( imaginary zeroes of real x^1/x when x> e^1/e) <0 and since q is a square root, both conjugate minimums along imaginary axis.
May be not yet.
So we take :
dI/dp= p*(h((I/p)^(p-2I)/I* ln(I/e*p) - I/(p^2))
And put it =0 to find minimum:
We have 2 solutions : p=0 and
h((I/p)^(p-2I)/I* ln(I/e*p) - I/(p^2)=0
h(((I/p)^(p-2I)/I)*ln(I/e*p))= I/(p^2) we can make substitution p^2=q
Than from earlier, if h( function) = I/q then from another thread http://math.eretrandre.org/tetrationforu...hp?tid=110
function = (I/q)^(q/I)
so (((I/(q^(1/2))^(q^(1/2)-2I)/I))*ln(I/(e*(q^(1/2)))) = (I/q)^(q/I)
So we can find q and p, probably both complex numbers.
The idea was, this should give the minimum of Gottfrieds curve in the left upper corner , where Re ( imaginary zeroes of real x^1/x when x> e^1/e) <0 and since q is a square root, both conjugate minimums along imaginary axis.
May be not yet.

