Understanding \(f(z,\theta) = e^{e^{i\theta}z} - 1\)
#3
Also, to give an idea of what I am going to do:

\[
\frac{d^{s}}{dw^s}\Big{|}_{w=0} \frac{e^{iw} + e^{-iw}}{2} -1 = \frac{i^s + (-i)^s}{2}= \cos(\frac{\pi s}{2})\,\,\text{when}\,\,0 < \Re(s) < 1
\]

Who's to say the same thing doesn't happen with \(\vartheta_\pi\)  Wink
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RE: Understanding \(f(z,\theta) = e^{e^{i\theta}z} - 1\) - by JmsNxn - 12/12/2022, 04:51 AM

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