Calculating the fractional iterates of \(f(z) = e^z-1\) to reasonable accuracy
#4
Hi James -

 thanks for your answer. Well, not all of the matrix stuff is faster than the `subst(poly,x,y)` method I had to learn... My first implementation using the matrix-based BASE interpretation in the integral needed about 100 times as much of your implementation. One can do big errors, since timing philosophy is little documented for Pari/GP ... Ok, changing order of evaluation and using real numbers instead of rational numbers I arrived at half of the speed of that `subst(subst())` construction.                

I've done a little test on the evaluation of the BASE-polynomial. I observed, that if we apply \(x\) values at the coefficients of the BASE at a certain power of \(z\), then that evaluation is equivalent to only a polynomial of small order with factor \( \exp(-x) \) , so for instance, of we use the coefficients \( c_{r,2} \) at \(z^2 \) we have something like \( f(x,2) = sum_{k=0}^\infty c_{k,2} x^k = (x^2-8x+2) \cdot \exp(-x) \) where the polynomial expression has higher orders when the coefficients \( c_{r,j} \) are taken from \( z^j \). But possibly you know this - its just my exploration of this somehow unfamiliar construction of the BASE.

Here is a list of the first few polynomials:
Code:
j    polynomial at z^j
- - - -- - - - - - - - - - - - - -
2  exp(-x)/(j-1)!/6* (6  )
3  exp(-x)/(j-1)!/6* (6 -   6x)
4  exp(-x)/(j-1)!/6* (6 -  24x +   9x^2)
5  exp(-x)/(j-1)!/6* (6 -  84x +  93x^2 -  18x^3 )
6  exp(-x)/(j-1)!/6* (6 - 306x + 765x^2 - 385x^3 +  45x^4)
7  exp(-x)/(j-1)!/6* (6 -1212x +6198x^2 -6110x^3 +6945x^4 - 135x^5 )
...

Unfortunately I've no idea at the moment how to find a significant pattern, but of course that polynomials could -for 21 coefficients at z-powers only- be manually determined and coded in the program. Even don't know whether this is efficient at all; I'll see.                  

As side effect: I'm happy to finally see the theta-function "in action": how it is and for what it is used, at least in one instance...

(work in progress...)
Gottfried Helms, Kassel
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RE: Calculating the fractional iterates of \(f(z) = e^z-1\) to reasonable accuracy - by Gottfried - 11/17/2022, 02:42 AM

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