Pentation Fractals
#4
(10/22/2022, 02:56 PM)Daniel Wrote:
(10/22/2022, 02:11 PM)bo198214 Wrote: Or more precisely: If \(c\) is the pixel value as a complex number, then the "tetration" fractal would be obtained by the iteration of \(f_c(z)=c^z\), so the "pentation" fractal would be obtained by the iteration of the function \(f_c(z)={}^zc\) while your fractal is obtained by iteration of which function?

I'm iterating \[^z(\sqrt{2})\].

You mean, you iterate \(f(z)={^z}(\sqrt{2})\) with initial value \(z_0=c\).
But a pentation fractal (in your terminology) would be to iterate \(f(z)={^z}c\) with initial value \(z_0=c\) or even \(z_0=0\) or \(z_0=1\).
Do you agree?
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Messages In This Thread
Pentation Fractals - by Daniel - 10/22/2022, 12:59 PM
RE: Pentation Fractals - by bo198214 - 10/22/2022, 02:11 PM
RE: Pentation Fractals - by Daniel - 10/22/2022, 02:56 PM
RE: Pentation Fractals - by bo198214 - 10/22/2022, 09:54 PM
RE: Pentation Fractals - by Daniel - 10/22/2022, 11:06 PM
RE: Pentation Fractals - by bo198214 - 10/23/2022, 07:32 AM

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