01/19/2008, 07:40 PM
Thanks
I had mistake in the sign of n=4 for I*pi/2 so correctly:
W(-n*(pi/2) - I*n*ln(n) ) = ln(n) - i*pi/2 for n>=2
for n=1 the sign at i(pi/2) is +..
The resulting formula for n>=2 can also be rewritten as:
W(-n*(pi/2)-I*n*ln(n))= ln(n/I)
but -n(pi/2)-I*n*ln(n) =-n*ln(I)/I-I*n*ln(n)= +I*n*(ln(I)-ln(n))
So W(I*n*ln(I/n)) = ln(n/I) and
W(ln((I/n)^(I*n)))=ln(n/I) which makes calculations for h simpler.
It seems to hold for all x>1; at x=1 sign changes for some reason.
W(ln((I/x)^(I*x)))=ln(x/I)
h((I/x)^(x/I))= (I/x)

I had mistake in the sign of n=4 for I*pi/2 so correctly:
W(-n*(pi/2) - I*n*ln(n) ) = ln(n) - i*pi/2 for n>=2
for n=1 the sign at i(pi/2) is +..
The resulting formula for n>=2 can also be rewritten as:
W(-n*(pi/2)-I*n*ln(n))= ln(n/I)
but -n(pi/2)-I*n*ln(n) =-n*ln(I)/I-I*n*ln(n)= +I*n*(ln(I)-ln(n))
So W(I*n*ln(I/n)) = ln(n/I) and
W(ln((I/n)^(I*n)))=ln(n/I) which makes calculations for h simpler.
It seems to hold for all x>1; at x=1 sign changes for some reason.
W(ln((I/x)^(I*x)))=ln(x/I)
h((I/x)^(x/I))= (I/x)

