(07/13/2022, 07:00 PM)JmsNxn Wrote: No, Daniel's right, there is no such function--at least no such analytic function. I doubt there's even a smooth function.How many times real differentiable do you think it could be?
Every analytic function must satisfy:
\[
\lim_{n\to\infty} \left(\frac{f^{(n)}(k)}{n!}\right)^{1/n} \le 1
\]
And it's safe to say:
\[
\lim_{n\to\infty} \left(\frac{^n a}{n!}\right)^{1/n} = \infty\\
\]
Do you have any more guesses about that?
Please remember to stay hydrated.
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\

