F(f(x))=exp(exp(x)).

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F(f(x))=exp(exp(x)).

Gottfried Offline

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07/01/2022, 07:05 AM

Hmm, you surely mean \(f(f(x))=\exp(\exp(x)) \) ?

Yes, using the Schroeder-method it needs only the switching of sign in one parameter to create such functions. I've fiddled with this idea once (2011) and took as an example the Zeta-function as iterable one.
See MO

It didn't follow much of this; I had not much space that time besides of my job - but I would really like to see some investigations for this!

Gottfried

Gottfried Helms, Kassel

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Messages In This Thread

F(f(x))=exp(exp(x)). - by Catullus - 07/01/2022, 06:10 AM

RE: F(f(x))=exp(exp(x)). - by Gottfried - 07/01/2022, 07:05 AM

RE: F(f(x))=exp(exp(x)). - by Catullus - 07/01/2022, 07:26 AM

RE: F(f(x))=exp(exp(x)). - by Gottfried - 07/01/2022, 07:30 AM

RE: F(f(x))=exp(exp(x)). - by tommy1729 - 07/01/2022, 08:40 PM

RE: F(f(x))=exp(exp(x)). - by JmsNxn - 07/01/2022, 08:54 PM

RE: F(f(x))=exp(exp(x)). - by tommy1729 - 07/01/2022, 09:03 PM

RE: F(f(x))=exp(exp(x)). - by JmsNxn - 07/01/2022, 09:11 PM