06/13/2022, 10:18 PM
(06/13/2022, 10:14 PM)tommy1729 Wrote:(06/13/2022, 08:29 PM)JmsNxn Wrote: \[
f(z) = A(z)\sin(2 \pi z) \sum_{n=0}^\infty \frac{a_n}{2\pi A(n) (z-n)}\\
\]
This satisfies:
\[
f(n) = a_n\\
\]
And you can force convergence of the series by letting \(A(n)\) be as large as possible. So for example \(A(z) = e^z\) works.
How does f(5) = a_5 follow from
\[
f(z) = \Exp(z)\sin(2 \pi z) \sum_{n=0}^\infty \frac{a_n}{2\pi \Exp(n) (z-n)}\\
\]
or
\[
f(5) = \Exp(5)\sin(2 \pi 5) \sum_{n=0}^\infty \frac{a_n}{2\pi \Exp(n) (z-n)}\\
\]
??
regards
tommy1729
not sure why tex fails
slightly better
How does f(5) = a_5 follow from
\[
f(z) = Exp(z)\sin(2 \pi z) \sum_{n=0}^\infty \frac{a_n}{2\pi Exp(n) (z-n)}\\
\]
or
\[
f(5) = Exp(5)\sin(2 \pi 5) \sum_{n=0}^\infty \frac{a_n}{2\pi Exp(n) (z-n)}\\
\]
??
regards
tommy1729

