- \(\forall x\:\tau(x,1)=1\)
- \(\forall y\in\Bbb{C-N}\:\tau(x,-y)=x\uparrow\tau(x,-y-1)\)
- For a given k, using \(\tau\) to do \(\text{sexp(slog(}x)+k)\) produces the same iteration of exponentials, (Or principled logarithms, if k is negative, and if possible,) for any branch of slog, if slog happens to branch.
- If \(\tau(x,y)\) approaches any of the fixed points or n-cycles of the function \(x\uparrow k\), it will approach continuously iterating \(m*y+b\).
- \(\tau\) is mostly holomorphic.
If so, is it unique?
Please remember to stay hydrated.
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\

