On the topic of the behavior of tetration. How slow does (e^-e)^^x converge anyway? as n becomes larger and larger (e^-e)^^n approaches e^-1 which is approximately .368. even (e^-e)^^16384~.375. Fun fact: 1/((e^-e)^^16384-e^-1) ~ 141.404. 141.404 ~ sqrt(2)*100.
Also maybe there should be a symbol for e^-e. (Also called the iterated exponential constant.) Like how there is a symbol for e^e^-1.
Also maybe there should be a symbol for e^-e. (Also called the iterated exponential constant.) Like how there is a symbol for e^e^-1.
Please remember to stay hydrated.
ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\