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tetration from alternative fixed point - Printable Version +- Tetration Forum (https://tetrationforum.org) +-- Forum: Tetration and Related Topics (https://tetrationforum.org/forumdisplay.php?fid=1) +--- Forum: Mathematical and General Discussion (https://tetrationforum.org/forumdisplay.php?fid=3) +--- Thread: tetration from alternative fixed point (/showthread.php?tid=452) |
RE: tetration from alternative fixed point - sheldonison - 06/28/2010 (06/27/2010, 06:02 AM)bo198214 Wrote:Henryk, I'm using the same equation you are. Instead of "-n", I mulitply by c^n before taking the log_c. This is mathematically equivalent, but it seems to help identify a unique branch point independent of the size of "n". Perhaps I can explain what I was trying to say with a graph of the SuperFunction (developed from the secondary fixed point), showing some contour lines. To generate these contours lines in the SuperFunction, I used the inverse super function with img(z)=-3pi*i contour with real(z) varying from \( +/-\infty \). Then I graph the exponent of that contour line, which is repeated one unit away, with img(z)=0 and real(z) varying from -\( \infty \) to 0, and the exponent of that contour line with img(z)=0 and real(z) varying from 0..1. The three contours are disconnected from each other, which I think you were pointing out to begin with. The Reimann mapping will not be analytic at the boundary points.(06/21/2010, 04:24 PM)sheldonison Wrote: I can make graphs of the real contour of the superfunction developed from the alternative fixed point, with singularities at 0, 1, e, e^e, e^e^e .... The pattern repeats, as shown by the "alt 3pi*i contour line." Each contour line would have alternates repeating endlessly in the diagonal direction. If you follow a path on the Reimann surface of the inverse superfunction from \( -\infty \) to \( +\infty \), the path you take will be along a diagonal. But yes, there will be singularities at 0,1,e,e^e, ... but only two of them will be of interest to the Riemann mapping. I don't think I'm explaining it very well, apologies. There are many other paths that can be be graphed in the SuperFunction from the alternate fixed point. I included the 2pi*i contour, and the pi*i contour as well, though they aren't my primary concern. They can also be used to generate repeating contour lines. This graph is in stark contrast to the superfunction from the primary fixed point, where the consecutive exponentiations fit each other like a glove, allowing the Riemann mapping to cancel out the singularity. - Sheldon
RE: tetration from alternative fixed point - bo198214 - 06/29/2010 (06/28/2010, 11:03 PM)sheldonison Wrote: Henryk, I'm using the same equation you are. Instead of "-n", I mulitply by c^n before taking the log_c. This is mathematically equivalent, I think it is not "equivalent" in the sense of "equal", because complex logarithm does not satisfy log(zw)=log(z)+log(w). I guess my formula lands on a completely different branch of slog, hm. Well I will try to reproduce your curves, with your formula. And dont think that my understanding is that much deeper, perhaps we indeed can develop a secondary fixed point real analytic slog, if we dont start with a "plain" initial region, but with an overlapping initial region/manifold. I am really interested in this unitude/multitude topic. (For example what happens with Kouznetsov's method if we just plug in the secondary fixed point pair?) RE: tetration from alternative fixed point - sheldonison - 07/01/2010 (06/29/2010, 06:53 AM)bo198214 Wrote: I think it is not "equivalent" in the sense of "equal", because complex logarithm does not satisfy log(zw)=log(z)+log(w). I guess my formula lands on a completely different branch of slog, hm. The path from the real axis to the secondary fixed point is much less direct. Kouznetsov's method requires three consecutive exponents, (he uses 0, 1, e), and their vertical (along increasing imaginary) paths to the fixed point. The path to the primary fixed point is fairly direct. But not the path to the secondary fixed point. For example, consider the path from real=ln(0.5), 0.5, and exp(0.5) to the secondary fixed point (via the i*3pi contour). These are the real values near the maximum of the i*3pi contour, (see graph in earlier post). Here is a graph of the first two. The third, exp(0.5) path to the secondary fixed point is already very chaotic, with img varying in the hundreds, so I left it off the graph. ![]() Notice how much more direct the path is to the primary fixed point is. Using this path to the primary fixed point as a seed, I would imagine Kouznetsov's method would converge very nicely. But it is difficult to imagine Kouzenetsov's method converging to anything meaningful for the path to the secondary fixed point (especially considering the even more chaotic exp(0.5) path). I also looked at the path to the secondary fixed point from i*pi contour, but that appears to be even less well behaved than the path via the i*3pi contour. - Sheldon
RE: tetration from alternative fixed point - bo198214 - 07/02/2010 (07/01/2010, 03:31 PM)sheldonison Wrote: But not the path to the secondary fixed point. For example, consider the path from real=ln(0.5), 0.5, and exp(0.5) to the secondary fixed point (via the i*3pi contour). These are the real values near the maximum of the i*3pi contour, (see graph in earlier post). Here is a graph of the first two. *nods* This is what I mean that we dont have an initial "plain" region (and I guess regardless how we choose the first curve, the second will always overlap the first or itself). In the best case we have some initial manifold (self overlapping region). But thats in the moment out of my sight how to apply Kouznetsov's method to a manifold. PS: Dont be shy to upload pictures to the forum. I consider it a long term archive (though a very unsorted yet), while I dont know how long referenced sites would live. RE: tetration from alternative fixed point - bo198214 - 07/21/2010 (07/01/2010, 03:31 PM)sheldonison Wrote: Kouznetsov's method requires three consecutive exponents, (he uses 0, 1, e), and their vertical (along increasing imaginary) paths to the fixed point. As I think a second time about it, why does he need paths to the fixed point? He integrates along the paths Re(z)=1, Re(z)=-1. He merely forces the value of the superfunction to be the fixed point for imaginary part going to infinity. How the path behaves while going to the fixed point is not essential for his computation, isnt it? RE: tetration from alternative fixed point - sheldonison - 07/21/2010 (07/21/2010, 03:24 AM)bo198214 Wrote:After reading the cauchy computation thread, I think the Cauchy algorithm is sensitive to getting a reasonable initial guess that is close enough to get convergence, and is also sensitive to updating the nodes in in an order that helps guarantee convergence.(07/01/2010, 03:31 PM)sheldonison Wrote: Kouznetsov's method requires three consecutive exponents, (he uses 0, 1, e), and their vertical (along increasing imaginary) paths to the fixed point. Are there any links on the forum with Riemann (Knesser's solution) mapping results? I remember Jay posted some results. I've been toying with very simple iterative Riemann mapping, and was able to get some semi-reasonable results. RE: tetration from alternative fixed point - sheldonison - 08/13/2010 (06/28/2010, 11:03 PM)sheldonison Wrote: ....To generate these contours lines in the SuperFunction, I used the inverse super function with img(z)=-3pi*i contour with real(z) varying from \( +/-\infty \). Then I graph the exponent of that contour line, which is repeated one unit away, with img(z)=0 and real(z) varying from -\( \infty \) to 0, and the exponent of that contour line with img(z)=0 and real(z) varying from 0..1. The three contours are disconnected from each other, which I think you were pointing out to begin with. The Reimann mapping will not be analytic at the boundary points.The complex periodicity is incorrect in this graph, which effects the "alternative 3*pi*i contour" graph. For the period I incorrectly used: period = 2Pi*i/L The correct value is period = 2Pi*i/(L-2*Pi*I) This is because the correct equation for the periodiicty is 2*Pi*i/ln(L) Because L>2Pi*I, the primary ln(L)=L-2*Pi*I. The correct complex period=1.3769+2.1751*I. I haven't verified the rest of the graph, but otherwise, I'm still using the same equations as I used when I made this graph, and those equations should have given correct values for the other complex contours. By the way, the equations are posted here. I found the problem when I wrote a pari-gp script for the secondary fixed point. With the fix, the alternative contour no longer fits snugly against the primary i=0 contour. I'm still interested in seeing if there's any way to Riemann map the contours back to a well defined real axis, but I still assume that it is not possible. - Sheldon RE: tetration from alternative fixed point - sheldonison - 11/18/2011 (08/13/2010, 03:53 PM)sheldonison Wrote:I'm pretty sure it is possible to generate an analytic sexp(z) function from the alternative fixed point after all! Looking at my older posts, I was also very very very close to seeing the solution 15 months ago. The problem is that there is more than one way to unwrap the inverse Schroder function into the complex plane, to generate the complex superfunction. From the best graph I previously posted, the correction for how to to unwrap the inverse Schroder function is to rotate the graph, and shrink it, so that superf(z+1)=exp(super(z)). But it would be better to just start over! Anyway, I have much prettier pictures this time, because I'm using Mike/Andy's complex graph coloring scheme.(06/28/2010, 11:03 PM)sheldonison Wrote: ....To generate these contours lines in the SuperFunction, I used the inverse super function with img(z)=-3pi*i contour with real(z) varying from \( +/-\infty \)....... With the fix, the alternative contours no longer fits snugly... I'm still interested in seeing if there's any way to Riemann map the contours back to a well defined real axis, but I still assume that it is not possible. Let's start with the complex superfunction from the secondary fixed point, L=2.0623 + 7.5886i. Here is a color plot of the complex superfunction. The period of the complex superfunction from the secondary fixed point is approximately 1.3769+2.17514i. If you notice the light grey contour, you're looking at where the complex superfunction traces out the real number line from roughly -infinity to 4,000,000, or roughly from sexp(-2) to sexp(3), or five periods of z+theta(z). The negative real numbers are graphed in cyan. One more unit to the left of the cyan/grey contour, would be the 3pi i imaginary contour. Notice, that its \( 3\pi i \) instead of \( \pi i \), because for this alternative solution, \( \Im(\text{sexp}(-3..-2))=3\pi i \). The grey contour needs to get z+theta(z) mapped, so that this grey line becomes the real axis of the alternative sexp(z). I don't know how to calculate the theta(z) mapping, or the mathematically equivalent Riemann mapping, because this alternative sexp(z) function is not nearly as well behaved as the sexp(z) from the primary fixed point. Notice how quickly the function starts misbehaving as real(z) increases and imag(z) increases, above the grey contour. But in theory, it should be possible to calculate a theta/Riemann mapping, which would generate a 1 to 1 bijection between the superfunction from the secondary fixed point, and the upper half of the complex plane. I have some ideas for how to calculate it, although the existing Kneser.gp algorithm will not converge. For comparison, here is the sexp(z) from the primary fixed point. Notice how nicely it is behaved, especially as imag(z) increases away from the real axis, and the function quickly converges to the primary fixed point! I also included the equivalent grey contour, for the real number line from roughly -infinity to 4,000,000, or sexp(-2) to sexp(3). Here is the path from log(0.5) to the secondary fixed point. I didn't even try to include all of the path from 0.5 vertical to the fixed point. The path is even more chaotic than in my earlier post, with the rotated graph superfunction graph. Finally, here is what the alternative sexp(z) graph would probably look like. As I said, I haven't calculated it yet, but this would have the requisite sexp(-3)..sexp(-2)=3pi i contour, where sexp(z) at integer values of z has the "z" term coefficient equal to 0, and the z^2 term coefficient also equal to zero. - Sheldon RE: tetration from alternative fixed point - sheldonison - 11/21/2011 (11/18/2011, 08:57 PM)sheldonison Wrote: I'm pretty sure it is possible to generate an analytic sexp(z) function from the alternative fixed point after all....I generated a taylor series and theta mapping, from the secondary fixed point. The complex plot is very pretty, and shows the z^3 pattern around sexp(z=-1). At the real axis, visually the sexp_l2(z) function looks as predicted in the previous post (see approximation graph). This sexp_l2(z) function is also analytic everywhere in the upper and lower half of the complex plane, with singularities at the real axis for integer values of z<=-2. So, this is another different analytic tetration solution for base(e), which meets all of the same requirements as the preferred solution, but obviously looks very different at the real axis, and in the complex plane, since it converges to the secondary fixed point, \( L2\approx 2.0623+7.58863i \), as imag(z) increases or as real(z) decreases. The period of the superfunction ~=1.3769+2.1751i \( =\frac{2\pi i}{\log(\log(L2))} \). Here, for the log(log(L2)), we use \( \log(\log(L2))=L2-2\pi i \). Initially, the mistake I made was to use \( \log(L2)=L2 \), which is a correct alternative way to unwrap the inverse schroder function to the complex plane to generate the superfunction, but it does not allow the theta(z) mapping to generate sexp(z). Like the solution using the primary fixed point, the limiting value for the lower half of the complex plane is the conjugate of the L2. Here is the graph, at a radius of 0.5, around z=-1, showing the three loops around the unit circle. Here is the taylor series, also generated around z=-1. I also generated a z+theta(z) for imag(z)>0.1i. To get the two series to converge towards each other, I had to get a very good seed value, and even then, convergence was very slow, requiring perhaps 50 iterations to get these results. The algorithm I used to generate a seed value was to start with sexp(z) from the primary fixed point, and use \( \text{sexp}(z-\sin(\frac{2\pi z} {2\pi})) \). I used that to generate an initial theta(z) mapping, which still required tweaking before I could get convergence. Also, I was only able to use a radius of about 0.7 for the sexp(z) function about z=-1, so I wasn't sure if that would converge or not. To help improve convergence, I needed a better initial seed. So I also had to generate a real valued Fourier transform, \( \text{sexp}(z+\theta_2(z) \), where theta2(z) had about a half a dozen terms. Both of these functions were iterated against \( \text{superf}_{L2}(z+\theta(z)) \). The taylor series below is accurate to about 32 decimal digits, when compared to \( \text{superf}_{L2}(z+\theta(z)) \) for imag(z)>0.1i. \( \text{sexp}_{L2}(z-1)=\sum_{n=0}^{\infty}a_n z^n \). After each iteration generating the sexp_l2 approximation at z=-1, from the superfunction approximation, I forced a0=0, a1=0, and a2=0, which was required for convergence. Code: sexp from 2nd fixed point taylor series, generated around sexp(-1)=0.RE: tetration from alternative fixed point - sheldonison - 12/05/2011 (11/21/2011, 11:19 PM)sheldonison Wrote: I generated a taylor series and theta mapping, from the secondary fixed point....Below, there are graphs of the sexp(z) from the secondary fixed point, at the real axis, from sexp(-1.5) to sexp(1.5). I also graphed the first and second derivatives, and the equivalent functions from the primary fixed point. Notice how the derivative goes to zero at integer values of z. I was able to get fairly clean convergence using two different algorithms, both with identical results. The simplest algorithm, with the quickest convergence required an initialization, very similar to the initialization used in the my kneser.gp program, followed by an initial approximation \( \text{sexp_{l2}}(z)=\text{sexp}(z-sin(2z\pi)/(2\pi)) \). The initial sexp(z) need only have three terms in its Taylor series. Then this initial approximation required an additional 42 iterations, generating a theta(z) approximation from the secondary fixed point, followed by an sexp(z) approximation, from both the theta(z) and the sexp(z) approximation around z=-1. This gave results accurate to ~32 decimal digits. At each iteration, I forced the first three terms in the Taylor series to zero. - Sheldon |