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On to C^\infty--and attempts at C^\infty hyper-operations - Printable Version +- Tetration Forum (https://tetrationforum.org) +-- Forum: Tetration and Related Topics (https://tetrationforum.org/forumdisplay.php?fid=1) +--- Forum: Hyperoperations and Related Studies (https://tetrationforum.org/forumdisplay.php?fid=11) +--- Thread: On to C^\infty--and attempts at C^\infty hyper-operations (/showthread.php?tid=1297) Pages:
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RE: On to C^\infty--and attempts at C^\infty hyper-operations - sheldonison - 03/02/2021 (03/01/2021, 11:22 PM)MphLee Wrote: I'm probably missing some key piece of the puzzle (terminology). Are you talking about a kind of inverse Schroeder-like function right? A confortable abuse of name similar to how we can call \( \phi_{n+1} \) inverse Abel-like function of \( \phi_{n} \)? Sorry for the confusion; yes you are correct. The Schroeder like function is Schroeder like only in that it has a formal power series beginning with x+a2x^2 ... and a multiplier at zero, with the multiplier=e. Since it is a formal series, we can get the formal inverse and generate a \( \Psi(x) \) function and then it turns out the function we're iterating is actually \( f(x)=e^{(x+1)}\cdot\Psi(x);\;\; \) This is the function James is actually iterating when he generates \( \phi \) \( \Psi(f(x))=e\cdot\Psi(x);\;\;\; \) Schroeder function and inverse formal definition using f(x) \( \Psi^{-1}(e\cdot~x)=f(\Psi^{-1}(x)) \) \( \phi(x)=\Psi^{-1}(e^x);\;\;\;\phi_n(x)=\Psi_n^{-1}(e^x);\;\; \) this works for n=2,3,4 .... The FPS (formal power series) approach is another intriguing approach to understanding \( \phi \), and the iterated \( \phi_n \) functions. The FPS approach would need more effort to make it rigorous; and the effort to make the FPS rigorous might become increasingly daunting for the iterated phi series for n>2. Even though \( \phi \) is entire, f has singularities where the derivative of \( \Psi^{-1} \) is equal to zero. Here is the Taylor series for f; the function we are actually iterating to generate \( \phi \), which has a fixed point of \( f(0)=0;\;f^{'}(0)=e \) Code: {f=Here are the first few Taylor series coefficients of the \( \Psi^{-1}(x) \) function which is entire. We can generate the individual terms with a closed form in terms of "e", but I don't have a generic equation for the closed form. The higher order pentation, and hexation \( \Psi_3^{-1};\;\Psi_4^{-1} \) also have similar formal series representations, which I have also generated. Code: xFinally, for completeness here are the first few Taylor series terms of the formal series for \( \Psi(x) \) Code: xRE: On to C^\infty--and attempts at C^\infty hyper-operations - JmsNxn - 03/02/2021 Hey Everyone. Haven't been on for a while, been a little busy. I thought I'd post the modified form of the paper. It details how to construct \( C^\infty \) hyper-operations; minus maybe a few details. But I'm confident I got everything down. In fact, I'm confident that if we do it in the manner Sheldon describes, using a sequence of infinite compositions, \( \phi_n(s) = \Omega_{j=1}^\infty \phi_{n-1}(s-j+z)\bullet z\\ \) Not much really changes. I chose to use the exponential convergents rather than the \( \phi_n \) convergents, simply because it generalizes well to the construction of arbitrary super-functions. All we need really is an exponential convergents. In fact, \( \phi_n \) will look pretty much similarly, because of its exponential nature. The better form of Sheldon's method is that we retain holomorphy. Since I'm only trying to show \( C^\infty \), I figure holomorphy isn't really needed. I do believe we could definitely use \( \phi_n(s) \) to construct \( e \uparrow^n x \). I believe it's more of an aesthetic issue, and I find it a bit more natural to just use, \( \Phi_n(s) = \Omega_{j=1}^\infty e^{s-j}e \uparrow^{n-1} z\bullet z\\ \) And do away with \( \phi \). Also because this satisfies the more natural equation, \( \Phi_n(s+1) = e^s e \uparrow^{n-1} \Phi_n(s)\\ \) And it removes a bit of the untangling if we were to use \( \phi_n \). Anyway, here's what I have so far. The proof of \( C^\infty \) hyper-operators is surprisingly copy/paste from the proof of \( C^\infty \) tetration, so long as you pay attention to the generalization, it should be fine. Any questions, comments or the what have you are greatly appreciated. I spent a lot of time restructuring the paper, but a lot of it is similar to what I wrote before. Thanks, James |